Matematika

Pertanyaan

sin 30 + tan 45 - cosec 60 / sec 30 + cos 60 + cot 45 ??

1 Jawaban

  • (sin 30 + tan 45 - cosec 60) / (sec 30 + cos 60 + cot 45)
    = (1/2 + 1 - (2√3)/3) / ((2√3)/3 + 1/2 + 1)
    = (3/6 + 6/6 - (4√3)/6) / ((4√3)/6 + 3/6 + 6/6)
    = ((9 - 4√3)/6) / ((9 + 4√3)/6)
    = (9 - 4√3) / (9 + 4√3) × (9 - 4√3)/(9 - 4√3)
    = (9 - 4√3)² / (9² - (4√3)²)
    = (81 - 72√3 + 48) / (81 - 48)
    = (129 - 72√3)/33

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