Ksp Zn(OH)2=1.10^-15. pH larutan jenuh Zn(OH)2 ....?
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            Ksp Zn(OH)2=1.10^-15. pH larutan jenuh Zn(OH)2 ....?
               
            
               1 Jawaban
            
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			  	1. Jawaban NInja1cakZn(OH)2 > Zn^2+ + 2OH^-
 s 2s
 Ksp = s . (2s)^2
 10^-15 = 4s^3
 maka s = 0.25 . 10^-5
 OH- = 2s
 = 2 . 0.25 .10^-5
 = 0.5 . 10^-5
 = 5 . 10^-6
 pOH = 6 - log 5
 pH = 14 - (6 - log 5)
 = 8 + log 5