Ksp Zn(OH)2=1.10^-15. pH larutan jenuh Zn(OH)2 ....?
Kimia
daffaanggun
Pertanyaan
Ksp Zn(OH)2=1.10^-15. pH larutan jenuh Zn(OH)2 ....?
1 Jawaban
-
1. Jawaban NInja1cak
Zn(OH)2 > Zn^2+ + 2OH^-
s 2s
Ksp = s . (2s)^2
10^-15 = 4s^3
maka s = 0.25 . 10^-5
OH- = 2s
= 2 . 0.25 .10^-5
= 0.5 . 10^-5
= 5 . 10^-6
pOH = 6 - log 5
pH = 14 - (6 - log 5)
= 8 + log 5