Fokus nomer 37 pliss dijawab cepet
Matematika
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Pertanyaan
Fokus nomer 37 pliss dijawab cepet
1 Jawaban
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1. Jawaban Jaliaa91
p x l = Luas
(2x-3) x (x+4) = 63
2x² + 8x - 3x + 12 = 63
2x² + 5x + 12 = 63
2x² + 5x = 75
2x² + 5x - 75 = 0
(x - 5)(2x + 15)
x = 5 atau x = -15/2
nilai x yg memenuhi adalah X = 5
P = 2x - 3
=> 2(5) - 3
=> 10 - 3
=> 7
L = x + 4
=> 5 + 4
=> 9