Diketahui barisan geometri U3=8 dan U5=32 maka U7 adalah?

U3 = 8 → ar² = 8
U5 = 32
ar⁴ = 32
(ar²)r² = 32
8r² = 32
r² = 32/8 = 4
r = 2
→ ar² = 8
a(2²) = 8
a = 2

U7 = a × r^6 = 2 × 2^6 = 128