ksp perak klorida AgCl : 3,6.10^-11 mol ^2L2. hitung kelarutan AgCl
Kimia
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Pertanyaan
ksp perak klorida AgCl : 3,6.10^-11 mol ^2L2. hitung kelarutan AgCl
1 Jawaban
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1. Jawaban hakimium
Kelarutan & Hasil Kali Kelarutan
Kimia XI
Misalkan kelarutan = s (mol/liter)
AgCl ⇄ Ag⁺ + Cl⁻
s s s
Ksp AgCl = [Ag⁺] [Cl⁻]
= [ s ] [ s ]
= s²
s = √ Ksp
s = √ [3,6 x 10⁻¹¹]
s = √ [36 x 10⁻¹²]
Jadi kelarutan AgCl sebesar 6 x 10⁻⁶ mol/liter