Larutan hcl 0.05 mempunyai ph sebesar

0.05 = 5 x 10`² =2-log 5

[H+] = a.Ma
[H+] = 1.5x10^-2
[H+] = 5x10^-2
pH = -log[H+]
pH = -log5x10^-2
pH = 2-log5