jika f(x) = 2x^2+3/x-6, maka f(0) + f'(0) adalah

f(x) = (2x^2 + 3)/(x - 6) = u/v => f(0) = (2.0^2 + 3)/(0 - 6) = 3/-6 = -1/2
u = 2x^2 + 3 => u' = 4x
v = x - 6 => v' = 1
f'(x) = (u' v - v' u)/ v^2
f'(x) = (4x (x - 6) - 1(2x^2 + 3))/(x - 6)^2
f'(0) = (4.0 (0 - 6) - 1(2.0^2 + 3)) / (0 - 6)^2
f'(0) = (0 - 3) / (-6)^2 = -3/36 = -1/12

f(0) + f'(0) = -1/2 + (-1/12) = (-6 - 1)/12 = -7/12