Dik segitiga ABC dgn sudut A=105°, Sudut C=45° dan panjang sisi AB=24cm berapa panjang sisi AC

<A + <B + <C = 180°
105° + <B + 45° = 180°
<B = 180° - 150° = 30°

AC/(sin B) = AB/(sin C)
AC/(sin 30°) = 24/(sin 45°)
AC/(1/2) = 24/(1/2 √2)
AC/1 = 24/√2
AC = 24/√2 . √2/√2 = (24√2)/2 = 12√2 cm