segitiga ABC diket b=30cm, sinA=3/5, sinC=4/5 hitung a. panjang a b. panjang c

Diket :
b = 30 cm
Sin A = 3/5 = 37°
Sin C = 4/5 = 53°
Sin B = 1 = 90°

Panjang a :
b/Sin B = a/Sin A
30/Sin 90 = a/Sin37
30/1 = a/ 3/5
30 = 5a/3
90 = 5a
90/5 = a
18 = a

Panjang c
b/Sin B = c/SinC
30/Sin 90 = c/Sin53
30/1 = c/ 4/5
30 = 5c/4
120 = 5c
24 = c

Jadi Panjang sisi a = 18 dan Sisi c = 24