tolong di jawab ya...

1) [tex] \lim_{x \to 4 } \frac{x^{2}-5x+6 }{x-2} = \lim_{x \to 4 } \frac{(x-2)(x-3)}{x-2} =4-3=1[/tex]
3) f(x) = x + 1 dan g(x) = 2x - 3
    a) (fog)(x) = f(2x - 3) = 2x - 3 + 1 = 2x - 2
    b) (gof)(x) = g(x + 1) = 2(x + 1) - 3 = 2x + 2 - 3 = 2x - 1
        (gof)(3) = 2x - 1 = 2 . 3 - 1 = 6 - 1 = 5