Tolong jawab yaaaaaa

sudut PQS + sudut SQR = 180° ➡ karena sudutnya berpelurus.
(3x-2)+(2x+2) = 180°
3x+2x = 180+2-2
5x = 180
x = 180/5
x = 36
maka,
besar sudut PQS
= (3x-2)
= 3(36)-2 ➡ nilai x dimasukkan
= 108-2
= 106° ( D )

Bab Sudut
Matematika SMP Kelas VIII

∠PQS + ∠SQR = 180°
3x - 2° + 2x + 2° = 180°
5x = 180°
x = 180° : 5
x = 36°

∠PQS = 3x - 2°
∠PQS = 3 . 36° - 2°
∠PQS = 108° - 2°
∠PQS = 106°

jawabannya D