Jika (f°g) (×) = x^2-2×-2 dan f(×) = ×-3 Makan nilai g (2) = ...

komposisi fungsi dan fungsi invers

f(x) = x - 3
fog(x) = x² - 2x - 2

f{ g(x) } = x² - 2x - 2
g(x) - 3 = x² - 2x - 2
g(x) = x² - 2x - 2 + 3
g(2) = (2)² - 2(2) -2 + 3
g(2) = 4 - 4 - 2 + 3
g(2) = 1

f o g = f(gx)
x^2 - 2x - 2 = g(x) -3
x^2 - 2x +1 = gx
2^2 - 2(2) + 1 = g(2)
4 - 4 + 1 = g(2)
g (2) = 1