Dik. akar-akar persamaan kuadrat x^2 - px + p + 1 = 0 ad/ x^1 dan x^2 jika x^2^1 + x^2^2 = 6 maka nilai p = A. -5 atau 3 B. -4 atau 2 C. -2 atau 4 D. -1 atau 3

x^2 - px + (p + 1) = 0
x1 + x2 = -b/a = -(-p)/1 = p
x1.x2 = c/a = (p + 1)/1 = p + 1

x1^2 + x2^2 = 6
(x1 + x2)^2 - 2 x1.x2 = 6
(p)^2 - 2(p + 1) = 6
p^2 - 2p - 2 = 6
p^2 - 2p - 8 = 0
(p - 4)(p + 2) = 0
p = 4 atau p = -2