tentukan nilai stasioner untuk fungsi f(x)=x3-12x+2

f(x) = x³ - 12x + 2
f'(x) = 3x² - 12 = 0
3(x² - 4) = 0
3(x - 2)(x + 2) = 0
ketemu x = 2 dan x = -2

Nilai stasioner f(x)
f(2) = 8 - 24 + 2 = -14
f(-2) = -8 + 24 + 2 = 18