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Pertanyaan

asam cuka CH3COOH 0,1 M (KA=10-5) Mempunyai pH....

1 Jawaban

  • [H+] =√ka.ma
    [H+] =√10^-5. 10^-1
    [H+] = √10^-6
    [H+] = 10^-3

    ph= -log[H+]
    ph= -log(10^-3)
    ph= 3

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