tolong bantu saya jawab no 27 yg ini buat remedi

tan α = 2b/2b
tan α = 1
α = 45°

cosec α + sec α = cosec 45° + sec 45° = √2 + √2 = 2√2

sisi miring= √2b^2+2b^2
               =√4b^2+4b^2
              =√8b^2
             =2b√2
sin a = 2b/2b√2 = 1/√2
cos a = 2b/2b√2 = 1/√2
cosec a + sec a
= 1/sin a +1/ cos 
=√2 +√2
=2√2