jika suatu fungsi f(x) = 3x²-5, hitunglah : a. f(5) f(-6) b. nilai '' p '' jika f(p) = 43 c. f(4) - f(-3) .....jawabannya harus lengkap yachh.....
Matematika
iky46
Pertanyaan
jika suatu fungsi f(x) = 3x²-5, hitunglah :
a. f(5) f(-6)
b. nilai '' p '' jika f(p) = 43
c. f(4) - f(-3)
.....jawabannya harus lengkap yachh.....
a. f(5) f(-6)
b. nilai '' p '' jika f(p) = 43
c. f(4) - f(-3)
.....jawabannya harus lengkap yachh.....
2 Jawaban
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1. Jawaban Aditaalvord
f (5) =3x25 - 5 =70
f(6)=3x36-5=103
f(p)=43 => 3X²-5=43
3X²=48
X²=48/3
X²=16
X=√16=4 => P=4
f(4)-f(3)=3x4²-5-(3x3²-5)=43-22=21 -
2. Jawaban rahmaay
a) f(5) = 3(5)²-5
= 3(25)-5
= 75-5
= 70
f(-6) = 3(-6)²-5
= 3(36)-5
= 108 - 5
= 103
b) f(p) = 3p²-5
f(p) = 43
3p²-5 = 43
3p² = 48
p² = 16
p = 4 atau p = -4
c) f(4) = 3(4)²-5
= 3(16)-5
= 48-5
= 45
f(-3) = 3(-3)²-5
= 3(9)-5
= 27 - 5
= 22
Jadi f(4) - f(-3) = 45-22 = 23
Semoga benar dan bermanfaat :)