tolong bantu yaa mkasihh

kuat arus
loop abcda
ΣE + ΣiR = 0
3 - 6 + i (5+1+2+3+1) = 0
-3 + 12 i = 0
12 i = 3
i = ¼ A,
searah putaran jarum jam

beda potensial
Vcd = i Rcd
Vcd = ¼ • 3
Vcd = ¾ V ← jwb