tolong plisss di kerjakan ya
            Kimia
            
               
               
            
            
               
               
             
            novan60
         
         
         
                Pertanyaan
            
            tolong plisss di kerjakan ya
               
         
         
               1 Jawaban
            
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			  	1. Jawaban arfzk1) n = JP/L
 =3,01 • 10^24/6,02 • 10²³
 = 5 mol
 w = n x ar
 = 5 x 59
 = 295g
 2)n = V/Vm
 = 10/22,4
 = 0,44 mol
 w = n x mr
 = 0,44 x 44
 = 19,6g
 3) n = V/Vm
 = 5,6/22,4
 = 0,25 mol
 w = n x mr
 = 0,25 x 16
 = 4g
 4) n NaOH = w/mr
 =2/40
 =0,05 mol
 100mL = 0,1L
 M = n/L
 = 0,05/0,1
 = 0,5M
 5) n Urea = w/mr
 = 3/60
 = 0,05 mol
 200g = 0,2kg
 m = n/kg
 = 0,05/0,2
 = 0,25m
 6) 12% = 12g glukosa dalam 100g larutan
 g pelarut = 100-12 = 88g
 88g = 0,088 kg
 n glukosa = w/mr
 = 12/180
 = 0,067 mol
 m = n/kg
 = 0,067/0,088
 = 0,76m
 7) 20% = 20g urea dalam 100g larutan
 g pelarut = 100-20 = 80g
 mol pelarut = w/mr = 80/18 = 4,44 mol
 mol urea = w/mr = 20/60 = 0,33 mol
 f Urea = mol Urea/mol urea + mol air
 = 0,33/0,33+4,44
 = 0,33/4,77
 = 0,07
 8) b NaCl = 50g
 b air = 150ml = 150g
 % berat= 50/150+50 x 100%
 = 50/200 x 100%
 = 25%
 9) V alkohol = 30mL
 V air = 150mL
 %volume = 30/150+30 x 100%
 = 30/180 x 100%
 = 16,67%