Kimia

Pertanyaan

tolong plisss di kerjakan ya
tolong plisss di kerjakan ya

1 Jawaban

  • 1) n = JP/L
    =3,01 • 10^24/6,02 • 10²³
    = 5 mol
    w = n x ar
    = 5 x 59
    = 295g

    2)n = V/Vm
    = 10/22,4
    = 0,44 mol
    w = n x mr
    = 0,44 x 44
    = 19,6g

    3) n = V/Vm
    = 5,6/22,4
    = 0,25 mol
    w = n x mr
    = 0,25 x 16
    = 4g

    4) n NaOH = w/mr
    =2/40
    =0,05 mol
    100mL = 0,1L
    M = n/L
    = 0,05/0,1
    = 0,5M

    5) n Urea = w/mr
    = 3/60
    = 0,05 mol
    200g = 0,2kg
    m = n/kg
    = 0,05/0,2
    = 0,25m

    6) 12% = 12g glukosa dalam 100g larutan
    g pelarut = 100-12 = 88g
    88g = 0,088 kg
    n glukosa = w/mr
    = 12/180
    = 0,067 mol
    m = n/kg
    = 0,067/0,088
    = 0,76m

    7) 20% = 20g urea dalam 100g larutan
    g pelarut = 100-20 = 80g
    mol pelarut = w/mr = 80/18 = 4,44 mol
    mol urea = w/mr = 20/60 = 0,33 mol
    f Urea = mol Urea/mol urea + mol air
    = 0,33/0,33+4,44
    = 0,33/4,77
    = 0,07

    8) b NaCl = 50g
    b air = 150ml = 150g
    % berat= 50/150+50 x 100%
    = 50/200 x 100%
    = 25%

    9) V alkohol = 30mL
    V air = 150mL
    %volume = 30/150+30 x 100%
    = 30/180 x 100%
    = 16,67%