jika f(x)=2x^2+3/x-6,maka f(0)+f'(0) adalah

f(x)= 2x²+3 / x-6
f(0)= 0+3 / 0-6
= -1/2
f'(x)= u'v - v'u / v²
= (4x)(x-6) - (1)(2x²+3) / (x-6)²
= 0 - 3 / 36
= -3/36
= -1/12

f(0)+f'(0)= -½-1/12 = -7/12