diketahui segitiga ABC dengan BC=4√2 cm, sudut A=45°, sudut B=30° .tentukan panjang AC?

AC/sin B = BC/sin A
AC/sin 30 = 4akar2/sin 45
AC * 1/2 akar 2 = 4akar2 * 1/2
AC * 1/2 akar 2 = 2 akar 2
AC = 4 cm

Mapel : Matematika
Kelas : X SMA
Bab : Trigonometri

Pembahasan :
Aturan Sinus

BC/Sin A = AC/Sin B
(4√2)/Sin 45° = AC/Sin 30°
(4√2)/(1/2 √2) = AC/(1/2)
2√2 = 1/2 √2 AC
AC = 4 cm