Koodinat titik balik fungsi y=2x-4x+8
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            Koodinat titik balik fungsi y=2x-4x+8
               
            
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			  	1. Jawaban AnonymeBab Fungsi Kuadrat
 Matematika SMP Kelas VIII
 y = 2x² - 4x + 8
 a = 2; b = -4; c = 8.
 sumbu simetri = x = -b/2a
 sumbu simetri = x = - (-4) / (2 . 2)
 sumbu simetri = x = 4/4
 sumbu simetri = x = 1
 y = 2 . 1² - 4 . 1 + 8
 y = 6
 koordinat = (1, 6)