Koodinat titik balik fungsi y=2x-4x+8
Matematika
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Pertanyaan
Koodinat titik balik fungsi y=2x-4x+8
1 Jawaban
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1. Jawaban Anonyme
Bab Fungsi Kuadrat
Matematika SMP Kelas VIII
y = 2x² - 4x + 8
a = 2; b = -4; c = 8.
sumbu simetri = x = -b/2a
sumbu simetri = x = - (-4) / (2 . 2)
sumbu simetri = x = 4/4
sumbu simetri = x = 1
y = 2 . 1² - 4 . 1 + 8
y = 6
koordinat = (1, 6)