Matematika

Pertanyaan

keliling lingkaran yg memiliki luas 616 cm

2 Jawaban

  • L = 616 cm²
    [tex] \pi [/tex]r² = 616 cm²
    22/7 x r² = 616 cm²
    r² = 616 cm² ÷ 22/7
    r² = 616 cm² x 7/22
    r² = 196 cm²
    r = √196 cm²
    r = 14 cm

    Keliling:
    = [tex] \pi [/tex](r x 2)
    = 22/7 x (14 x 2)
    = 22/7 x 28
    = 88 cm
  • Rumus Luas = 22/7 x r²
    616cm ² = 22/7 x r²
    r² = 616cm² : 22/7 = 616cm² x 7/22
    r² = 196cm
    r = 14cm
    Rumus Keliling = 22/7 x diameter
    Kel = 22/7 x (2 x 14) = 22/7 x 28 = 88cm

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