[tex] \lim_{x \to \infty} \frac{(3x-6)(x^2-2x)}{(2x^2-8)(6x-12)} [/tex]
Matematika
tegarsurya81
Pertanyaan
[tex] \lim_{x \to \infty} \frac{(3x-6)(x^2-2x)}{(2x^2-8)(6x-12)} [/tex]
1 Jawaban
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1. Jawaban gumball3point
dapat difaktorkan menjadi
[tex] \lim_{x \to \infty} \frac{(3x-6)(x-2)x}{2(x-2)(x+2)2(3x-6)} = \lim_{x \to \infty} \frac{x}{4(x+2)} = \frac{1}{4} \lim_{x \to \infty} \frac{x}{x+2}= \frac{1}{4}* 1[/tex]
maka
[tex] \lim_{x \to \infty} \frac{(3x-6)(x^2-2x)}{(2x^2-8)(6x-12)}= \frac{1}{4} [/tex]