Matematika

Pertanyaan

Mohon bantuannya teman-teman
Mohon bantuannya teman-teman

1 Jawaban

  • Langsung aja y

    nomor 1
    f(x) = x³ + 3x + 5
    f(2+k) = (2+k)³ + 3(2+k) + 5
    f(2+k) = k³+6k²+12k+8+6+3k+5
    f(2+k) = k³ + 6k² + 15k + 19

    nomor 2
    lim (x²+3x-10) / (x²+x-6)
    x→2

    lim (x + 5)(x - 2) / (x - 2)(x + 3)
    x→2

    lim (x + 5) / (x + 3)
    x→2

    = (2+5) / (2+3)
    = 7/5

    nomor 3
    f(x) = x² + x
    g(x) = 2 / (x+3)

    (f-g)(x) = f(x) - g(x)

    = (x² + x) - 2 / (x+3)
    = x³ + 4x² + 3x - 2 / (x+3)

    (f-g)(3) = 3³+4(3)²+3(3)-2 / (3+3)
    (f-g)(3) = 27+36+9-2 / 6
    (f-g)(3) = 70/6

    nomor 4

    lim (t² + 7t + 6) / (t² - 4t - 5)
    t→1

    lim (t + 6)(t + 1) / (t + 1)(t - 5)
    t→1

    lim (t + 6) / (t - 5)
    t→1

    = (1+6) / (1-5)
    = 7/(-4)
    = - 7/4

    semoga berguna +_+