faktorkan a.) 10x² + 17x + 3 b.) 2p² - 19p + 9 c.) 4a² + 7a - 2 d.) 2b² - 5b - 7
            Matematika
            
               
               
            
            
               
               
             
            aisyahmaya40
         
         
         
                Pertanyaan
            
            faktorkan 
a.) 10x² + 17x + 3
b.) 2p² - 19p + 9
c.) 4a² + 7a - 2
d.) 2b² - 5b - 7
               
            a.) 10x² + 17x + 3
b.) 2p² - 19p + 9
c.) 4a² + 7a - 2
d.) 2b² - 5b - 7
               2 Jawaban
            
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			  	1. Jawaban riaya. (2x+3)(5x+1)
 b. (2p-1)(p-9)
 c. (4a-1)(a+2)
 d. (2b-7)(b+1)
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			  	2. Jawaban Diahmercurya). (2x + 3) (5x + 1)
 10[tex] x^{2} [/tex] + 17x + 3 = [tex] \frac{(10x + 15) (10x + 2)}{10} [/tex]
 = [tex] \frac{5(2x + 3) 2(5x + 1)}{10} [/tex]
 = (2x + 3) (5x + 1)
 b). (p - 9) (2p - 1)
 2[tex] p^{2} [/tex] - 19p + 9 = [tex] \frac{(2p - 18) (2p - 1)}{2} [/tex]
 = [tex] \frac{2(p - 9)(2p - 1)}{2} [/tex]
 = (p - 9) (2p - 1)
 c). (a + 2) (4a - 1)
 4[tex] a^{2} [/tex] + 7a - 2 = [tex] \frac{(4a + 8)(4a - 1)}{4} [/tex]
 = [tex] \frac{4(a + 2)(4a - 1)}{4} [/tex]
 = (a + 2)(4a - 1)
 d). (b + 1) (2b - 7)
 2[tex] b^{2} [/tex] - 5b - 7 = [tex] \frac{(2b + 2)(2b - 7)}{2} [/tex]
 = [tex] \frac{2(b + 1)(2b - 7)}{2} [/tex]
 = (b + 1)(2b - 7)
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