Minta tolong yah sayang... PR kenaikan kelas

Ot = 12 , ab = 18cm , bc =10cm

A.) = panjang te =
√12^2 + (1/2 .18)^2 =
√144 + 9^2 =
√144 + 81 =
√225 =
15cm

B.) Panjang tf =
√12^2 + (1/2 . 10)^2 =
√144 + 5^2 =
√144 + 25 =
√169 =
13cm

C.) Luas abt =
A × t / 2 = 18 × 15 / 2 = 135cm^2

D.) Luas bct =
A × t / 2 = 10 × 13 / 2 = 65cm^2

E.) Luas permukaan =
Luas alas + 2(luas abt) + 2(luas bct) =
(18×10) + 2(135) + 2(65) =
180 + 270 + 130 =
580cm^2

F.) Volume =
1/3 × luas alas × tinggi =
1/3 × 18 × 10 × 12 =
720cm^3

Kalau boleh jadikan jawaban terbaik yah.