10logx = b -> 10xlog100= ?

alog b = c -> b = ac    alog b = log b/ log a

x = 10b

10.10blog100

log 100 /log 10 . 10b

2 log 10 / log 10 + b log 10

2/1+b

Diketahui:
¹⁰logx = b

Ditanya:
¹⁰ˣlog100 = ??

Jawab:
¹⁰ˣlog100 
= (log100)/(log10x)
= (log10²)/(log10 + logx)
= (2.1)/(1 + b)
= 2/(1 + b)