koordinat titik balik maksimumu dari grafik fungsi f(x)= x3+12x2+1

Titik balik  fungsi

f(x) = x³  + 12x² + 1
f'(x) ' = 0
3x² + 24x = 0
3x(x + 8) =0
x = 0 atau x= -8

f(0) = 0³+12.0² + 1 --> f(0) = 1
f(-8) = 257

f'(x) = 3x² +24x
f "(x) = 6x +24
f"(0)= 6(0) + 24 = 24 ---> f" (0) > 0 --> titk (0,1) min
f "(-8) = 6(-8) +24 = - 24 --> f "(x) < 0 --> titk(-8, 257) mak