mohon bantuanya ya ka
            Matematika
            
               
               
            
            
               
               
             
            dimasteguhprasetiyi
         
         
         
                Pertanyaan
            
            mohon bantuanya ya ka
               
         
         
               1 Jawaban
            
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			  	1. Jawaban SadonoSukirnob + q = -b/a = -(-p)/2 = p/2
 b.q = c/a = 1/2
 1/b² + 1/q² = -b/a
 (b²+q²)/(b.q)² = -(-5)/1 = 5
 {(b+q)²-2p.q}/(1/2)² = 5
 {(p/2)² - 2(1/2)}/(1/4) = 5
 {p²/4 - 1} × 4 = 5
 p² - 4 = 5
 p² = 5+4
 p² = 9
 p = 3 atau -3
 1/b² + 1/q² = c/a
 1/(b.q)² = q
 1/(1/2)² = q
 1/(1/4) = q
 4 = q
 q - p = 4 - 3 = 1
 atau
 4 - (-3) = 7