penyelesaian persamaan 3^2xkuadrat +5x-3 =27^2x+3 adalah a dan b, nilai a.b... a.-6 b.-3 c.3 d.5 e.1

[tex] 3^{ 2x^2 + 5x - 3} = 27^{2x + 3} \\ 3^{2x^2 + 5x-3} = (3^3)^{2x + 3} \\ 3^{2x^2 + 5x - 3} = 3^{6x + 9} \\ 2x^2 + 5x - 3 = 6x + 9 \\ 2x^2 + 5x - 3 -6x - 9 = 0 \\ 2x^2 - x - 12 = 0 \\ \\ a ~ . ~ b = \frac{c}{a} \\ a~.~b = \frac{-12}{2} \\ a~.~b = -~6 [/tex]