²log3= a Dan ³log7 = b, maka 2+ab / 1+2a =

²log3.³log7 = ab
²log7 = ab
maka 2 + ab = ²log2² + ²log7
= ²log4 + ²log7
= ²log28
basisnya 2 ya
→
1+2a = ²log2 + ²log3²
= ²log(2x9)
= ²log18

maka 2+ab / 1+2a = ²log28 / ²log18
atau ^18log28